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{SECT 0 {EXCHG {PARA 18 "" 0 "" {TEXT -1 9 "Calculo I" }}{PARA 256 "" 
0 "" {TEXT -1 36 "Li\347\343o 17: O Teorema de Valor do Meio" }}}
{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "restart: " }}}{EXCHG {PARA 0 
"" 0 "" {TEXT -1 28 "Recorde o Teormea de Rolle: " }}{PARA 0 "" 0 "" 
{TEXT -1 28 "Deixe f ser a fun\347\343o tal que" }}{PARA 0 "" 0 "" 
{TEXT -1 32 "       1) f \351 continua em [a,b] " }}{PARA 0 "" 0 "" 
{TEXT -1 33 "       2) f \351 diferente em (a,b) " }}{PARA 0 "" 0 "" 
{TEXT -1 23 "       3) f(a) = f(b). " }}{PARA 0 "" 0 "" {TEXT -1 52 "D
epois, existe algum c em (a,b) tal que f '(c) = 0. " }}}{EXCHG {PARA 
0 "" 0 "" {TEXT -1 43 "1) Use o Teorema de Rolle para mostrar que " }
{XPPEDIT 18 0 "3*x - 2 + cos( Pi*x/2" "6#,(*&\"\"$\"\"\"%\"xGF&F&\"\"#
!\"\"-%$cosG6#*(%#PiGF&F'F&F(F)F&" }{TEXT -1 31 " tem exatamente uma r
aiz real. " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 37 "f1:= x -> 3*x
 - 2 + cos( Pi * x / 2);" }{TEXT -1 0 "" }}{PARA 11 "" 1 "" {XPPMATH 
20 "6#>%#f1Gf*6#%\"xG6\"6$%)operatorG%&arrowGF(,(*&\"\"$\"\"\"9$F/F/\"
\"#!\"\"-%$cosG6#,$*&#F/F1F/*&%#PiGF/F0F/F/F/F/F(F(F(" }}}{EXCHG 
{PARA 0 "" 0 "" {TEXT -1 60 "Vamos desenhar f1 para ver aonde as ra
\355zes s\343o localizadas. " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 
0 47 "plot(f1(x), x = -4 * Pi.. 4 * Pi, color = red);" }{TEXT -1 0 "" 
}}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 13 "" 1 "" {GLPLOT2D 400 300 
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LTG" 1 2 0 1 10 0 2 6 1 4 2 1.000000 45.000000 45.000000 0 0 "Curve 1
" }}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 44 "Isto aparece ser precisament
e uma raiz real." }}{PARA 0 "" 0 "" {TEXT -1 54 "Vamos pegar numericam
ente o Maple para resolver isto. " }}}{EXCHG {PARA 0 "> " 0 "" 
{MPLTEXT 1 0 28 "fsolve(f1(x) = 0, x = 0..5);" }{TEXT -1 0 "" }}{PARA 
11 "" 1 "" {XPPMATH 20 "6#$\"+Z2ncR!#5" }}}{EXCHG {PARA 0 "" 0 "" 
{TEXT -1 56 "Assim, aparece que a raiz real de f1 [e aproximadamente \+
" }{XPPEDIT 18 0 ".3956670747;" "6#-%&FloatG6$\"+Z2ncR!#5" }{TEXT -1 
2 ". " }}{PARA 0 "" 0 "" {TEXT -1 63 "Como verificar nosso calculo num
\351rico com o Teorema de Rolle ? " }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}
{PARA 0 "" 0 "" {TEXT -1 62 "Suponha o contr\341rio que f1 tem 2 ou ma
is raiz real; disse a,b " }}{PARA 0 "" 0 "" {TEXT -1 45 "s\343o raiz r
eal de f1, ex., f1(a) = f1(b) = 0. " }}{PARA 0 "" 0 "" {TEXT -1 66 "De
pois pelo Teorema de Rolle l\341 existe algum c entre a e  b, com  " }
}{PARA 0 "" 0 "" {TEXT -1 31 "f1 '(c) = 0. Mas f1 '(x) = 3 - " }
{XPPEDIT 18 0 "Pi;" "6#%#PiG" }{TEXT -1 9 " /2 sin( " }{XPPEDIT 18 0 "
Pi;" "6#%#PiG" }{TEXT -1 21 " x/2 ) . Desde |sin( " }{XPPEDIT 18 0 "th
eta;" "6#%&thetaG" }{TEXT -1 10 " )| < = 1 " }}{PARA 0 "" 0 "" {TEXT 
-1 10 "pata todo " }{XPPEDIT 18 0 "theta;" "6#%&thetaG" }{TEXT -1 18 "
 , n\363s temos que |" }{XPPEDIT 18 0 "Pi;" "6#%#PiG" }{TEXT -1 9 " /2
 sin( " }{XPPEDIT 18 0 "Pi;" "6#%#PiG" }{TEXT -1 13 " x/2 )| < =  " }
{XPPEDIT 18 0 "Pi;" "6#%#PiG" }{TEXT -1 9 " /2 < 3. " }}{PARA 0 "" 0 "
" {TEXT -1 66 "Assim, f1 '(x) > 0 para todo x e assim n\363s temos uma
 contradi\347\343o. " }}{PARA 0 "" 0 "" {TEXT -1 41 "Logo, f1 tem prec
isamente uma raiz real. " }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "
" 0 "" {TEXT -1 63 "Vamos desenhar f1 '(x) para ver que realmente isto
 \351  > 0.     " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 45 "plot(D(
f1)(x), x = -4*Pi..4*Pi, color = red);" }{TEXT -1 0 "" }}{PARA 13 "" 
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0 0 "Curve 1" }}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 74 "2)  Suponha que \+
um objeto ande numa linha com fun\347\343o de posi\347\343o dada por: \+
" }{XPPEDIT 18 0 "s(t) = t/2 - sin(t)" "6#/-%\"sG6#%\"tG,&*&F'\"\"\"\"
\"#!\"\"F*-%$sinG6#F'F," }{TEXT -1 2 ". " }}{PARA 0 "" 0 "" {TEXT -1 
87 " Encontre aonde a velocidade instant\342nea iguala com a velocidad
e m\351dia no intervalo [0," }{XPPEDIT 18 0 "Pi;" "6#%#PiG" }{TEXT -1 
4 " ]. " }}{PARA 0 "" 0 "" {TEXT -1 19 " Desenhe a figura. " }}}
{EXCHG {PARA 0 "" 0 "" {TEXT -1 42 "Primeiro vamos desenhar a fun\347
\343o posi\347\343o. " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 22 "s:
= t -> t/2 - sin(t);" }{TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }
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wGF(,&*&#\"\"\"\"\"#F/9$F/F/-%$sinG6#F1!\"\"F(F(F(" }}}{EXCHG {PARA 0 
"> " 0 "" {MPLTEXT 1 0 35 "plot(s(t), t = 0..Pi, color = red);" }
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{TEXT -1 139 "A partir do desenho, n\363s vemos que o objeto primeiram
ente move para a esquerda e para a origem e depois continuamente move \+
para a direita. " }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" 
{TEXT -1 46 "A Velocidade m\351dia do objeto no intervalo [0, " }
{XPPEDIT 18 0 "Pi;" "6#%#PiG" }{TEXT -1 14 "] \351 dada por: " }}
{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 13 "         \+
( s(" }{XPPEDIT 18 0 "Pi;" "6#%#PiG" }{TEXT -1 15 ") - s(0) ) / ( " }
{XPPEDIT 18 0 "Pi;" "6#%#PiG" }{TEXT -1 9 " - 0 ) . " }}{PARA 0 "" 0 "
" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 60 "A Velocidade instant
\344nea no tempo c \351 dada por '(c). Assim, " }}{PARA 0 "" 0 "" 
{TEXT -1 37 "n\363s somos perguntados para resolver: " }}{PARA 0 "" 0 
"" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 13 "         ( s(" }
{XPPEDIT 18 0 "Pi;" "6#%#PiG" }{TEXT -1 15 ") - s(0) ) / ( " }
{XPPEDIT 18 0 "Pi;" "6#%#PiG" }{TEXT -1 17 " - 0 ) = s '(c); " }}
{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 20 "Precisame
nte o MVT. " }}{PARA 0 "" 0 "" {TEXT -1 1 " " }}}{EXCHG {PARA 0 "> " 
0 "" {MPLTEXT 1 0 6 "s(Pi);" }{TEXT -1 0 "" }}{PARA 11 "" 1 "" 
{XPPMATH 20 "6#,$*&\"\"#!\"\"%#PiG\"\"\"F(" }}}{EXCHG {PARA 0 "> " 0 "
" {MPLTEXT 1 0 5 "s(0);" }{TEXT -1 0 "" }}{PARA 11 "" 1 "" {XPPMATH 
20 "6#\"\"!" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 5 "D(s);" }
{TEXT -1 0 "" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#f*6#%\"tG6\"6$%)operat
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0 "" 0 "" {TEXT -1 25 "N\363s precisamos resolver: " }{XPPEDIT 18 0 "1
/2 = 1/2 - cos(t)" "6#/*&\"\"\"F%\"\"#!\"\",&*&F%F%F&F'F%-%$cosG6#%\"t
GF'" }{TEXT -1 15 " para t em [0, " }{XPPEDIT 18 0 "Pi;" "6#%#PiG" }
{TEXT -1 34 " ], ex.,  n\363s queremos cos(t) = 0 " }}{PARA 0 "" 0 "" 
{TEXT -1 14 "para t em [0, " }{XPPEDIT 18 0 "Pi;" "6#%#PiG" }{TEXT -1 
19 "]. A Solu\347\343o \351 t = " }{XPPEDIT 18 0 "Pi;" "6#%#PiG" }
{TEXT -1 50 " /2. Vamos desenhar a figura com a linha secante  " }}
{PARA 0 "" 0 "" {TEXT -1 27 "entre os pontos (0, 0) e ( " }{XPPEDIT 
18 0 "Pi;" "6#%#PiG" }{TEXT -1 2 ", " }{XPPEDIT 18 0 "Pi;" "6#%#PiG" }
{TEXT -1 39 " /2 ), e com a linha tangente para t = " }{XPPEDIT 18 0 "
Pi;" "6#%#PiG" }{TEXT -1 6 " /2 . " }}{PARA 0 "" 0 "" {TEXT -1 31 "As \+
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0 11 "D(s)(Pi/2);" }{TEXT -1 0 "" }}{PARA 11 "" 1 "" {XPPMATH 20 "6##
\"\"\"\"\"#" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "s(Pi/2);" }
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